write a program in c++ that calculate leap year

Example 4 if,else statement:

logic:

         here the main logic is that "the year which will divide by 4 and reminder is zero then the year will be leap otherwise not" so we take the modules of year by and check the year is leap or not.

program:

#include "stdafx.h"

#include "iostream"

#include "conio.h"

using namespace std;

void main()

{

int year;

cout<<"enter the year==";

cin>>year;

if(year%4==0)

cout<<"leap year";

else

cout<<"not a leap year";

_getch();

}

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